一 回顾trait使用
https://blog.csdn.net/bushuwei/article/details/103514174
发现之前本人说明很模糊,自己居然不知道为什么
其实这里的$c,就是class B
再次回顾逻辑
二 分析
- self和static区别说的没毛病
- Trait基类use trait,本类不use。那么如果用的new self,则你new 出来的就是 use trait者。如果new static,则因为有继承关系, 它会判断类是否存在(父子会被认为都是同一个static,则不再new),那么,谁先调用instance,那么new出来的就是谁。‘Trait基类use trait,本类不use’->直接‘其实这里的$c,就是class B’是错的。之所以有这个‘幻觉’,是因为单例模式,且static
三 上代码
- self+单例
trait A{ private static $instance; static function getInstance() { if(!isset(self::$instance)){ self::$instance = new self(); } return self::$instance; } } class B{ use A; function a() { var_dump('call at B'); } } class C extends B{ function a() { var_dump('call at c'); parent::a(); } } class D extends B{ use A; function a() { var_dump('call at D'); parent::a(); } } $b = B::getInstance(); $c = C::getInstance(); $d = D::getInstance(); $c->a(); echo "<br/>"; $d->a(); echo "<br/>";
string(9) "call at B" string(9) "call at D" string(9) "call at B"
注视掉
// $b = B::getInstance();
结果不变 - static+单例
trait A{ private static $instance; static function getInstance() { if(!isset(self::$instance)){ self::$instance = new static(); } return self::$instance; } } class B{ use A; function a() { var_dump('call at B'); } } class C extends B{ function a() { var_dump('call at c'); parent::a(); } } class D extends B{ use A; function a() { var_dump('call at D'); parent::a(); } } $b = B::getInstance(); $c = C::getInstance(); $d = D::getInstance(); $c->a(); echo "<br/>"; $d->a(); echo "<br/>";
string(9) "call at B" string(9) "call at D" string(9) "call at B"
注视掉
// $b = B::getInstance();
string(9) "call at c" string(9) "call at B" string(9) "call at D" string(9) "call at B"
-
self+非单例
trait A{ private static $instance; static function getInstance() { self::$instance = new self(); return self::$instance; } } class B{ use A; function a() { var_dump('call at B'); } } class C extends B{ function a() { var_dump('call at c'); parent::a(); } } class D extends B{ use A; function a() { var_dump('call at D'); parent::a(); } } $b = B::getInstance(); $c = C::getInstance(); $d = D::getInstance(); $c->a(); echo "<br/>"; $d->a(); echo "<br/>";
string(9) "call at B" string(9) "call at D" string(9) "call at B"
注释掉
// $b = B::getInstance();
结果不变
- static+非单例
trait A{ private static $instance; static function getInstance() { // if(!isset(self::$instance)){ // self::$instance = new static(); // } // return self::$instance; self::$instance = new static(); return self::$instance; } } class B{ use A; function a() { var_dump('call at B'); } } class C extends B{ function a() { var_dump('call at c'); parent::a(); } } class D extends B{ use A; function a() { var_dump('call at D'); parent::a(); } } $b = B::getInstance(); $c = C::getInstance(); $d = D::getInstance(); $c->a(); echo "<br/>"; $d->a(); echo "<br/>";
string(9) "call at c" string(9) "call at B" string(9) "call at D" string(9) "call at B"
注释掉
$b = B::getInstance();
结果不变
四 结论
- self的话,就是谁use的,就是谁
- static的话,谁调用的就是谁
- 但是static会出现‘谁use就是谁’的幻觉,那是因为单例模式,前面创建了相同类型的单例。
文章评论